来函数检测结果如下:
该公式没有未来函数


FH1:=REF(C,3)/REF(C,4)>1.095 AND BETWEEN(REF(L,2)/REF(C,3),1.02,0.98) AND BETWEEN(REF(L,1)/REF(C,3),1.02,0.98) AND H/REF(C,1)>1.02 ;

FH2:=REF(C,4)/REF(C,5)>1.095 AND BETWEEN(REF(L,3)/REF(C,4),1.02,0.98) AND BETWEEN(REF(L,2)/REF(C,4),1.02,0.98) AND BETWEEN(REF(L,1)/REF(C,4),1.02,0.98);

FH3:=REF(C,5)/REF(C,6)>1.095 AND BETWEEN(REF(L,4)/REF(C,5),1.02,0.98) AND BETWEEN(REF(L,3)/REF(C,5),1.02,0.98) AND BETWEEN(REF(L,2)/REF(C,5),1.02,0.98) AND BETWEEN(REF(L,1)/REF(C,2),1.02,0.98);

FH4:=NOT(COUNT(REF(C,1)/REF(C,2)>1.09,2)) AND L/REF(L,1)>0.97;

回头确认:(FH1 OR FH2 OR FH3) AND FH4 AND C/REF(C,1)>1.02;

 


原理解析:
FH1赋值:3日前的C/4日前的C>1.095 AND BETWEEN(2日前的L/3日前的C,1.02,0.98) AND BETWEEN(1日前的L/3日前的C,1.02,0.98) AND H/1日前的C>1.02
FH2赋值:4日前的C/5日前的C>1.095 AND BETWEEN(3日前的L/4日前的C,1.02,0.98) AND BETWEEN(2日前的L/4日前的C,1.02,0.98) AND BETWEEN(1日前的L/4日前的C,1.02,0.98)
FH3赋值:5日前的C/6日前的C>1.095 AND BETWEEN(4日前的L/5日前的C,1.02,0.98) AND BETWEEN(3日前的L/5日前的C,1.02,0.98) AND BETWEEN(2日前的L/5日前的C,1.02,0.98) AND BETWEEN(1日前的L/2日前的C,1.02,0.98)
FH4赋值:NOT(COUNT(1日前的C/2日前的C>1.09,2)) AND L/1日前的L>0.97
输出回头确认:(FH1 OR FH2 OR FH3) AND FH4 AND C/1日前的C>1.02
 

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